Activator.CreateInstance problem

Soulless

I have added a method to my main form that is generic and will open a
window given the window name as a string. Unfortunatley, it fails...

Here is the method:

private void OpenWindow(string asFormName)
{
foreach (Form f in this.MdiChildren)
{
if (asFormName == f.GetType().ToString())
{
f.Activate();
return;
}
}

Form loForm =
(Form)Activator.CreateInstance(Type.GetType(asForm Name));
loForm.MdiParent = this;
loForm.Show();
}


I call the method: OpenWindow("fornname");

This line fails: Form loForm =
(Form)Activator.CreateInstance(Type.GetType(asForm Name));

I get: value cannot be null.

Any why I am getting null?

Thanks!

Mattias Sjögren

>Any why I am getting null?

Type.GetType returns null if it can't find the type ("fornname" in
this case). Maybe you've misspelled the type name, or you're missing
the namespace.


Mattias

--
Mattias Sjögren [C# MVP] mattias @ mvps.org
|
Please reply only to the newsgroup.

Soulless

On Dec 10, 3:45 pm, Mattias Sjögren <>
wrote:
> >Any why I am getting null?
>
> Type.GetType returns null if it can't find the type ("fornname" in
> this case). Maybe you've misspelled the type name, or you're missing
> the namespace.
>
> Mattias
>
> --
> Mattias Sjögren [C# MVP] mattias @ mvps.orghttp://www.msjogren.net/dotnet/|
> Please reply only to the newsgroup.

It's odd. I verified that the form name is correct. I had not
considered it a namespace issue but will take a look. Thanks.

Soulless

On Dec 10, 3:45 pm, Mattias Sjögren <>
wrote:
> >Any why I am getting null?
>
> Type.GetType returns null if it can't find the type ("fornname" in
> this case). Maybe you've misspelled the type name, or you're missing
> the namespace.
>
> Mattias
>
> --
> Mattias Sjögren [C# MVP] mattias @ mvps.orghttp://www.msjogren.net/dotnet/|
> Please reply only to the newsgroup.

Thanks, yes, I needed to affix my namespace info before the form name.