crontab question

YZXIA

I am having diffculty with running cron job on my Solaris 8 box.

We are currently using C_Shell on our Solaris UNIX system. Every time
my schedule job is ran I get the following error message:

/export/home/xia_j/call_checkSeller: sqsh: not found

cron isnt reading the enviorment variables from .cshrc. How do I
configure the crontab so that the above issue is resolved

Thank You

boyd

In article <1167769690.454384.165200@42g2000cwt.googlegroups. com>,
"YZXIA" <yzx27@hotmail.com> wrote:

> I am having diffculty with running cron job on my Solaris 8 box.
>
> We are currently using C_Shell on our Solaris UNIX system. Every time
> my schedule job is ran I get the following error message:
>
> /export/home/xia_j/call_checkSeller: sqsh: not found
>
> cron isnt reading the enviorment variables from .cshrc. How do I
> configure the crontab so that the above issue is resolved
>
> Thank You

The cron program usually uses just sh, not csh, so it doesn't see the
..cshrc. You can set the environment something like this in the crontab:
(not tested)

29 * * * * ( myvar='this'; export myvar; /usr/local/bin/dowhat >
/usr/local/log/dowhat.log 2>&1 )

Boyd

Keith Thompson

boyd <tbmoore9@verizon.net> writes:
> In article <1167769690.454384.165200@42g2000cwt.googlegroups. com>,
> "YZXIA" <yzx27@hotmail.com> wrote:
>
>> I am having diffculty with running cron job on my Solaris 8 box.
>>
>> We are currently using C_Shell on our Solaris UNIX system. Every time
>> my schedule job is ran I get the following error message:
>>
>> /export/home/xia_j/call_checkSeller: sqsh: not found
>>
>> cron isnt reading the enviorment variables from .cshrc. How do I
>> configure the crontab so that the above issue is resolved
>>
>> Thank You
>
> The cron program usually uses just sh, not csh, so it doesn't see the
> .cshrc. You can set the environment something like this in the crontab:
> (not tested)
>
> 29 * * * * ( myvar='this'; export myvar; /usr/local/bin/dowhat >
> /usr/local/log/dowhat.log 2>&1 )

Easier:

29 * * * * myvar='this' /usr/local/bin/dowhat > /usr/local/log/dowhat.log 2>&1

If you really need all the settings from your .cshrc, you can do this:

29 * * * * csh -c "source .cshrc ; some_command"

Or you can write a wrapper script that handles whatever settings you
want and then invokes your target program, then just invoke the
wrapper script from your crontab.

--
Keith Thompson (The_Other_Keith) kst-u@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.

Michael Tosch

Keith Thompson wrote:
> boyd <tbmoore9@verizon.net> writes:
>> In article <1167769690.454384.165200@42g2000cwt.googlegroups. com>,
>> "YZXIA" <yzx27@hotmail.com> wrote:
>>
>>> I am having diffculty with running cron job on my Solaris 8 box.
>>>
>>> We are currently using C_Shell on our Solaris UNIX system. Every time
>>> my schedule job is ran I get the following error message:
>>>
>>> /export/home/xia_j/call_checkSeller: sqsh: not found
>>>
>>> cron isnt reading the enviorment variables from .cshrc. How do I
>>> configure the crontab so that the above issue is resolved
>>>
>>> Thank You
>> The cron program usually uses just sh, not csh, so it doesn't see the
>> .cshrc. You can set the environment something like this in the crontab:
>> (not tested)
>>
>> 29 * * * * ( myvar='this'; export myvar; /usr/local/bin/dowhat >
>> /usr/local/log/dowhat.log 2>&1 )
>
> Easier:
>
> 29 * * * * myvar='this' /usr/local/bin/dowhat > /usr/local/log/dowhat.log 2>&1
>
> If you really need all the settings from your .cshrc, you can do this:
>
> 29 * * * * csh -c "source .cshrc ; some_command"
>

will source it *twice*, because
csh always sources .cshrc unless invoked with -f.
To source it *once*, it must be

csh -c "some_command"
or
csh -fc "source .cshrc ; some_command"


--
Michael Tosch @ hp : com

Keith Thompson

Michael Tosch <eedmit@NO.eed.SPAM.ericsson.PLS.se> writes:
> Keith Thompson wrote:
[...]
>> If you really need all the settings from your .cshrc, you can do
>> this:
>> 29 * * * * csh -c "source .cshrc ; some_command"
>>
>
> will source it *twice*, because
> csh always sources .cshrc unless invoked with -f.
> To source it *once*, it must be
>
> csh -c "some_command"
> or
> csh -fc "source .cshrc ; some_command"

Yes, thanks for the correction.

--
Keith Thompson (The_Other_Keith) kst-u@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.